Additionally, assuming that 54321 is > unsigned int max on a non compliant system, the “L” suffix wont help because the compiler is being told to only allocated storage for ‘unsigned int’ – truncation will occur in this non-compliant case – but if you have a non-compliant compiler, you are pretty much fubar.

Just one note about the line :
“unsigned int salt[] = {12345, 54321};”
those number literals can be truncated by the compiler. Use the “L” suffix to fix it as in :
“unsigned int salt[] = {12345L, 54321L};”

It doesn’t cause a problem in your program but I just wanted to point it out ;) cheers

unsigned char out[16],out1[16];
unsigned char in[]=”qwertyuiopasdfgh”;
AES_KEY key1;
key1.rounds=256;
AES_encrypt(in,out, &key1);
AES_decrypt(out,out1,& key1);

I did not give any input to key1.rd_key.
When i am printing in and out1. Are not same. Is here any help.

echo “this is a test”| openssl enc -aes-256-cbc -a -salt -S 123456 -pass pass:mypass123
U2FsdGVkX1/BWCjmoDS864uoNI77IN69YsdAcvQ/QbU=

in your example I changed some parts as:
unsigned char *salt = “123456″
char *input = “this is a test”;
key_data = “mypass123″;

and first decoded base64 using this
http://www.openssl.org/docs/crypto/BIO_f_base64.html

but unfortunately I am not succesful :( I am not so good in crypto algorşthms though. Would you please show how can I decrypt aes_256_cbc + base64 encoded text?